Front a solid cylinder o!
holiowed out. Find the total surface area of the remaining solid.
Draw a pair of tangents to a circle of radius 8 cm which are inclined to each other at an angle of 120
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Answer:
Given:
Height (h) of cylindrical part = height (h) of the conical part =7 cm
Diameter of the cylindrical part =12 cm
Therefore, Radius (r) of the cylindrical part =
2
12
=6 cm
So, Radius of the conical part =6 cm
Slant height (l) of conical part =
r
2
+h
2
cm
=
6
2
+7
2
=
36+49
=
85
≈9.22 cm.
The total surface area of the remaining solid = CSA of the cylindrical part + CSA of the conical part + Base area of the circular part
=2πrh+πrl+πr
2
=2×
7
22
×6×7+
7
22
×6×9.22+
7
22
×6×6
=264+173.86+113.14
=551 cm
2
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