Question

Frustum of a right circular cone has a diameter of base 20 cm top 12 cm and height 3 cm

Answer 1

Answer:

Step-by-step explanation:

Given that Radius of Base is R=10cm: {Radius=Diameter/2}

Bottonm radius, r=6;

Height=3cm;

Area is =$\pi (R+r)\sqrt{(R-r)^{2}+h^{2}  }$;

Area of Frustum=$\pi (10+6)\sqrt{(10-6)^{2}+3^{2}  }$

Area=251.2 sq. cm