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hey here is your answer
hope it helps
if we connect first 4 ohm and 12 ohm resistant in paraller
then the equivalent will be 3ohm( u can find it by 1/R=1/R1+1/R2)
and then 3ohm and 2ohm will be connected in series
so equivalent will be 3+2=5ohm (by formula R=R1+R2)
see attachment for the figure
hope it helps
if we connect first 4 ohm and 12 ohm resistant in paraller
then the equivalent will be 3ohm( u can find it by 1/R=1/R1+1/R2)
and then 3ohm and 2ohm will be connected in series
so equivalent will be 3+2=5ohm (by formula R=R1+R2)
see attachment for the figure
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Anonymous:
thanks for brainliest bro
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