Math, asked by charul15, 10 months ago

full explanation.please solve correct answer will explanation I will mark you brainliest.​​

Attachments:

Answers

Answered by daveheer69
3

Answer:

k=1

Step-by-step explanation:

f(x)= x²+ax-6

g(x)= x²+bx+2

here, (x+2)=0 therefore x= -2

therefore, +(-2) = (-2)² + (-2)a-6 =0

4-2a-6=0

-2=2a

a= -1 _________equation (1)

g(-2) = (-2)² + (-2)b + 2

4-2b+2=0

6-2b

b=3____________equation(2)

kx²-ax-(a+b)

a = (-1) and b=3

therefore kx²+x-2=0

(x=2) = (-2)²k = -2-2=0

4k=4

k=1

Answered by BrainlyConqueror0901
6

\blue{\bold{\underline{\underline{Answer:}}}}

\green{\tt{\therefore{Value\:of\:k=1}}}

\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}

 \green{\underline \bold{Given : }}  \\  \tt:  \implies  {x}^{2}  + ax - 6  = 0 \\  \\ \tt:  \implies {ax}^{2}  + bx  + 2 =  0 \\  \\ \tt:  \implies {kx}^{2}  - ax - (a + b) = 0 \\  \\ \tt:  \implies Common \: factor = x + 2 \\  \\ \red{\underline \bold{To \: Rind : }}  \\  \tt:  \implies Value \: of \: k=?

• According to given question :

 \tt \circ \: x + 2 = 0 \implies x =  - 2 \\  \\  \bold{As \: we \: know \: that} \\  \tt :  \implies p(x)  =  {x}^{2}  + ax - 6 = 0 \\  \\ \tt :  \implies p( - 2)  =( - 2)^{2}   + a \times ( - 2) - 6 = 0 \\  \\ \tt :  \implies 4  - 2a   - 6 = 0 \\  \\ \tt :  \implies 2a =  - 2 \\  \\  \green{\tt :  \implies a =  - 1} \\  \\  \bold{Similarly : } \\  \tt:  \implies  p(x) = {x}^{2}  + bx + 2 = 0 \\  \\  \tt:  \implies  p( - 2) =( - 2)^{2}  + b \times ( - 2) + 2 = 0 \\  \\ \tt:  \implies 4  - 2b + 2 = 0 \\  \\ \tt:  \implies 2b = 6 \\  \\  \green{\tt:  \implies b = 3} \\  \\  \bold{For \: value \: of \: k : } \\ \tt:  \implies p(x) =  {kx}^{2}  - ax  - (a + b) = 0 \\  \\ \tt:  \implies p( - 2) =k \times ( - 2)^{2}   - ( - 1) \times ( - 2) - ( - 1 + 3) = 0 \\  \\ \tt:  \implies 4k - 2 - 2 = 0 \\  \\ \tt:  \implies 4k = 4 \\  \\  \green{\tt:  \implies k = 1} \\  \\   \green{\tt \therefore value \: of \: k \: is \: 1}


BrainlyAnswerer0687: perfect
Similar questions