Question

Full explanation plzz​

Answer 1

Answer:

2 - 28 mL

Explanation:

See the attachment for details

Answer 2

Answer:

(1) 5.61 ml

Explanation:

First let us know what happens when we mix KMnO4 with H2O2 in acidic medium.

2KMnO4+ 5H2O2+ 3H2SO4 → 5O2+ 2MnSO4+ K2SO4+ 8H2O

» 2 moles of KMnO4 releases 5 moles of O2

» 1 mole of KMnO4 releases 2.5 moles of O2

Given, 50 ml of 0.2M KMnO4

no.of.moles = Molarity × Volume in liters

no.of.moles = 0.2×1/(50/1000)

= 0.001 moles

» 0.001 moles of KMnO4 releases 0.0025 moles of O2

» 1 mole ----> 22400ml

» 0.0025 mole ----> 56ml of O2

To release 56 ml of O2, 56ml of 1V H2O2 is req or 5.6ml of 10V H2O2 is required.

Hence 5.6ml of 10V H2O2 is required.