Question

Full Mark:
30.
TIME:1 hour
Q1. The highest mark of a class is 3 more than three times the lowest mark. If the highest mark is 96,
find the lowest mark of the class.
[5]
Q2. What should be added to the sum of 3a + 2b +40 and 2b-3c +a to get a -4b +2c.
(5]
in
Q3. In the given figure lines I and mare parallel and line n is a
transversal. Find a, b, c, d, e, f, g by using the figure
[5]
a 66
bc
de
gf
(answer any five from angles a, b, c, d, e, fand g)
Q4.
Copy the figure given below and answer the following question.
A, B, C, D, E And O are different points. Lines AB and CD meet at O.
1
sa
2
E
4
3
a) Is adjacent to 2?
b) is adjacent to?
c) Is and form a linear pair?
d) Is are supplementary?
e) is tically opposite to angle 4?
[5]
a
Q5. a) In the figure given alongside AB is parallel to CD. Ef
transversal meet AB at P and CD at Q.
Identify one pair of
(i) corresponding angle
(ii) one pair of alternate interior angle
[2]
b) ABC is a triangle whose vertex angle is 70°. Other two
base angles are equal. Find each base angle.
[3]
(1 x 5= 5)
Q6.
Fill in the blanks.
angles
a) If the sum of two angles is 90° then the angles are
b) If two different lines say a and b are intersected by another line cat two different points, the line
cis called a
c) For what value of x the statement 4x + 1 = 9 is a solution of the given equation.
d) Write the given statement in the equation form "6 is taken away from twelve times of number x
results 16."
e) What will be the result when you take away-7x + 3y from 4y-x​

Answer 1

Answer:

let the highest mark be ×

the lowest mark of a class be y

condition 1

highest mark is 3 more than 3times the lowest

i.e x=3+3y

x-3y=3. (equation 1)

condition2

if highest mark is 96

i.e x=96

finf y

therefore put x=96 in equantion 1

x-3y=3

96-3y=3

96-3=3y

93=3y

93/3=y

31=y

ans- if highest mark is 96 then lowest mark is 31

2)

let the term added to get ans -4b+2c be x

therefore

x=(-4b+2c)-{(3a+2b+40)+(2b-3c+a)}

x=(-4b+2c)-{3a+2b+40+2b-3c+a}

x=(-4b+2c)-{3a+a+2b+2b+40-3c}

x=(-4b+2c)-{4a+4b+40-3c}

x=-4b+2c-4a-4b-40+3c

x=-8b+5c-4a-40

ans-. -8b+5c-4a-40 this term should be added to get ans -4b+2c