Full marks of two examination paper are in the ratio 2:3. A candidate obtains 60% marks in the first paper and 70% in the two papers, taken together. What percentage of marks did he get in the second paper?
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Full marks of two examination papers are in the ratio of 2 : 3. A candidate obtains 60% marks in the first paper and 70% in the two papers, taken together.
To find : the percentage of marks got by him in the second paper.
solution : let full marks of 1st and 2nd papers are 2k and 3k respectively.
obtained marks in the first paper = 60% of 2k
= 60 × 2k/100 = 1.2k
obtained marks in both papers = 70% of (2k + 3k)
= 70 % of 5k
= 70 × 5k/100
= 3.5k
so the candidate obtains mark in the second paper = 3.5k - 1.2k = 2.3k
marks in percentage = 2.3k/3k × 100
= 230/3
= 76.67 %
Therefore the candidate got 76.67 % marks in the second paper.
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