Question

full method answer.​

Answer 1

Answer:

hope it's helpful

mark me brainlist please

Answer 2

Answer:

Given,

1) $\sf\dfrac{2}{9}+ \dfrac{4}{9}$

2) $\sf\dfrac{7}{19}- \dfrac{11}{19}$

To Find :

values of those given fractions.

solution :-

1)  $\sf\dfrac{2}{9}+ \dfrac{4}{9}$

as the denominator is same i.e 9 we can directly add :-

$\frac{2 + 4}{9}$

$\frac{6}{9}$

$\frac{2}{3}$

$\sf\therefore$  $\sf\dfrac{2}{9}+ \dfrac{4}{9}$ = $\sf\dfrac{2}{3}$

2) $\sf\dfrac{7}{19}- \dfrac{11}{19}$

as there is same denominator i.e 19 we can directly subtract it :

$\frac{7 - 11}{19}$

$\frac{-4}{19}$

$\sf\therefore$  $\sf\dfrac{7}{19}- \dfrac{11}{19}$ = $\sf\dfrac{-4}{19}$.