Question

full method fraction please​

Answer 1

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Step-by-step explanation:

$4\left(2\times 7+3\right)\left(\frac{5}{4}+\frac{2\times 7+1}{7}\right)=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$4\left(14+3\right)\left(\frac{5}{4}+\frac{2\times 7+1}{7}\right)=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$4\times 17\left(\frac{5}{4}+\frac{2\times 7+1}{7}\right)=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$68\left(\frac{5}{4}+\frac{2\times 7+1}{7}\right)=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$68\left(\frac{5}{4}+\frac{14+1}{7}\right)=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$68\left(\frac{5}{4}+\frac{15}{7}\right)=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$68\left(\frac{35}{28}+\frac{60}{28}\right)=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$68\times \left(\frac{35+60}{28}\right)=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$68\times \left(\frac{95}{28}\right)=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$\frac{68\times 95}{28}=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$\frac{6460}{28}=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$\frac{1615}{7}=4\left(2\times 7+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

$\frac{1615}{7}=4\left(14+2\right)\times \left(\frac{5}{14}\right)+4\left(2\times 7+3\right)\times \left(\frac{2\times 7+1}{7}\right)$

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