Full question: The system PCl5(g)PCl3(g)+Cl2(g) attains equilibrium. If the equilibrium concentration of PCl3(g) is doubled, the concentration of Cl2(g) would become
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Answered by
1
Answer:
1/2 times.
Explanation:
Kc = [PCl3] [Cl2]. -(I)
[PCl5]
Let the new concentration of Cl2 be [Cl2]'
Kc for new equilibrium = 2[PCl3] [Cl2]'. -(II)
[PCl5]
Value of Kc does not changes on changing the equilibrium concentration.
So from (I) and (II)
[PCl3] [Cl2] = 2[PCl3] [Cl2]'
[PCl5] [PCl5]
=> [Cl2]/2 = [Cl2]'
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