Question

Full solution answer answer answer answerQ7And all full solution ​

Answer 1

Answer:

{vii} ( 4x + y) ( 5x - 3y)

= 4x(5x - 3y) + y(5x - 3y)

= 20x^2 - 12xy + 5xy - 3y^2

= 20x^2 - 3y^2 - 7xy

{viii} (2x + 3) (2x - 3)

= use (a+b)(a-b) = a^2 - b^2

= (2x)^2 - (3)^2

= 4x^2 - 9

{ix} (x^2 + 2y^2) ( x^2 - 7y^2 )

= (x^2 + 2y^2) {(x)^2 - (√7 y)^2}

= (x^2 + 2y^2) (x + √7 y)(x - √7 y)

{x} ( 2x + 2/3 ) (2x + 3/4)

= 2x(2x + 3/4) + 2/3( 2x + 3/4)

= 4x^2 + 3x/2 + 4x/3 + 1/2

= (24x^2 + 9x + 8x + 3)/6

= 1/6(24x^2 + 17x + 3)

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Answer 2

Answer:

{vii} ( 4x + y) ( 5x - 3y)

= 4x(5x - 3y) + y(5x - 3y)

= 20x^2 - 12xy + 5xy - 3y^2

= 20x^2 - 3y^2 - 7xy

{viii} (2x + 3) (2x - 3)

= use (a+b)(a-b) = a^2 - b^2

= (2x)^2 - (3)^2

= 4x^2 - 9

{ix} (x^2 + 2y^2) ( x^2 - 7y^2 )

= (x^2 + 2y^2) {(x)^2 - (√7 y)^2}

= (x^2 + 2y^2) (x + √7 y)(x - √7 y)

{x} ( 2x + 2/3 ) (2x + 3/4)

= 2x(2x + 3/4) + 2/3( 2x + 3/4)

= 4x^2 + 3x/2 + 4x/3 + 1/2

= (24x^2 + 9x + 8x + 3)/6

= 1/6(24x^2 + 17x + 3)