Question

full solution of this question.
fast​

Answer 1

Step-by-step explanation:

(a + b + c)³ - a³ - b³ - c³

⇒ (a + b)³ + c³ + 3(a + b)²c + 3(a + b)c² - a³ - b³ - c³

⇒ a³ + b³ + 3a²b + 3ab² + c³ + 3(a + b)²c + 3(a + b)c² - a³ - b³ - c³

⇒ a³ + b³ + 3ab(a + b) +c³ +  3(a + b)c [a + b + c] - a³ - b³ - c³

⇒ 3ab(a + b) + 3(a + b)c[a + b + c]

⇒ 3(a + b)[ab + ca + cb + c²]

⇒ 3(a + b)[a(b + c) + c(b + c)]

⇒ 3(a + b)(b + c)(c + a)

Hope it helps. If helped, mark as brainliest!