Math, asked by xaxoxo7877, 7 months ago

full solution send kro
please​

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Answers

Answered by singlamuskan107
0

Answer:

(i) 4abc

(ii) -5a^2b^2c^2

(iii) -2x^2y^4

Answered by sagalkaur
1

Answer:

i)4ab

ii)-5a²b²c²

iii)-2x²y⁴

Step-by-step explanation:

i)88ab²c²÷22bc²

we cancel out the common value i.e b,c²

88ab÷22

4ab

ii)-40a³b³c³÷8abc

common items=a,b,c

-40a²b²c²÷8

-5a²b²c²

iii)16x⁶y⁶÷(-8x⁴y²)

common items=x⁴ and y²

16x²y⁴÷(-8)

-2x²y⁴

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