Question

full working please .... with answer ​

Answer 1

Given :-

${\dfrac{p}{q}}\: =\: ({\dfrac{2}{3}})^2\: \div\: ({\dfrac{6}{7}})^0$

To Find :-

The value of $({\dfrac{q}{p}})^3$

Solution :-

$({\dfrac{2}{3}})^2\: \div\: ({\dfrac{6}{7}})^0$

$=\: {\dfrac{2 \times 2}{3 \times 3}}\: \div\: 1$ (since anything to the power 0 is 1)

$=\: {\dfrac{4}{9}}$

A/q,

${\dfrac{p}{q}}\: =\: {\dfrac{4}{9}}$

Therefore, P = 4 and Q = 9

Now,

$({\dfrac{q}{p}})^3$

$=\: ({\dfrac{9}{4}})^3$ (Since P = 4 and Q = 9 )

$=\: {\dfrac{9 \times 9 \times 9}{4 \times 4 \times 4}}$

$=\: {\dfrac{729}{64}}$

= 11.39

Therefore, value of $({\dfrac{q}{p}})^3$ is 11.39