Question

FUN TIME
5-digit number puzzle :
all you find a five digit number which has no zeros no digit is repea
The first digit is a prime number.
The second digit is the fifth digit minus the first digit.
The third digit is twice the first digit.
The fourth digit is the third digit plus three.
The fifth digit is the difference between the first digit and
the fourth digit.
ANSWER=​

Answer 1

Given :

• It is non-zero number.

• First digit is a prime number

• Second digit is (5th digit - 1st digit )

• Third digit is twice the 1st digit

• Fourth digit is (3rd digit + 3)

• Fifth digit is (4th digit - 1st digit )

To Find :

• 5 digit number

Solution :

Let the digit at first place be A,second place be B, third place be C, fourth place be D and fifth place be E

Hence,Number is ABCDE

$\bullet \sf \:1st \: Case$

First digit is a prime number.

It means A = 2,3,5 or 7

$\bullet \sf \:2nd \: Case$

Second digit is (5th - 1st)

It means B = (E - A)

$\bullet \sf \:3rd \: Case$

Third digit is twice the first digit

It means C = 2A

$\bullet \sf \:4th \: Case$

Fourth digit is third digit + 3

It means D = C + 3

$\bullet \sf \:5th \: Case$

Fifth digit is difference between the first and fourth digit.

It means E = D - A

Now,When C = 2A, We've to multiply the digit with 2 so that it gives only a digit number. From this we can conclude that 5 and 7 can't be the first digit as (5×2) = 10 and (7×2) = 14 which is a two digit number.

Hence,A = 2 or 3

3 can't be that digit because

C = 2 × A = E = 2 × A + A - A = 2 × A

Now, We've A = 2

$\dag \large \sf \: A = 2 \:$

$\dag \large \sf \: C = 2(2) = 4$

$\dag \large \sf \: D = 2(2) + 3 = 7$

$\dag \large \sf \: E = 7 - 2 = 5$

$\dag \large \sf \: B = 5 - 2 = 3$

$\bigstar \: \sf \purple{ Number = \boxed{ \sf \: 2} \boxed{ \sf \:3 } \boxed{ \sf \: 4} \boxed{ \sf \: 7} \boxed{ \sf \: 5}}$

Answer 2

https://t.me/vdntchall