Question

function.
write the domain of the
g(x)= square root of x-2
​

Answer 1

Answer:

x belongs to [2, infinity)

Step-by-step explanation:

For √(x-2) to exist, x-2 has to be equal to or greater than 0..cuz square root of -ve no. do not exist is set of real numbers

so, x-2 >= 0

or x>= 2

Answer 2

Answer:

GIVEN FUNCTION :–

$g(x) = \sqrt{x - 2}$

TO FIND DOMAIN :–

$x - 2 \geqslant 0$

$x \geqslant 2$