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If f(x) = 9 x+ 5 is a relation from R to R then find f^-1 and find f ^-1( 3)
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Given,
f ( x) = 9x + 5
To find inverse function, let's see if it's a bijective function.
It is a bijective function as it is a linear function.
Taking f ( x) = y as the range of bijective function is co - domain.
y = 9x + 5
y -5 = 9x
y -5 /9 = x
x = y -5 /9
We know that, f(x)= y then x = f^-1(y)
f^-1(y)= y -5/9
Replacing by x
f^-1(x) = x-5/9
Now, f^-1 = { x,x-5/9 }
And
f^-1(3)=3-5/9 = -2/9
Hope helped! ^^
f ( x) = 9x + 5
To find inverse function, let's see if it's a bijective function.
It is a bijective function as it is a linear function.
Taking f ( x) = y as the range of bijective function is co - domain.
y = 9x + 5
y -5 = 9x
y -5 /9 = x
x = y -5 /9
We know that, f(x)= y then x = f^-1(y)
f^-1(y)= y -5/9
Replacing by x
f^-1(x) = x-5/9
Now, f^-1 = { x,x-5/9 }
And
f^-1(3)=3-5/9 = -2/9
Hope helped! ^^
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