Math, asked by sissy2908, 8 months ago

fund a eq. of tangent to the curve y=(x-7)/((x-2)(x-3)) at the point it cuts the x-axis
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Answers

Answered by Anonymous
8

refer to the attachment

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Answered by MysteriousAryan
1

Answer:

We have given y=x-7/(x-2)(x-3) ................................(i) Let (i) cuts the x-axis at (x, 0) then x-7/(x-2)(x-3) =0 =>x=7 the required point is (7, 0).

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