Question

Fund determinant value of
2
3
1-)
3
2
2
Ire
3
1-)​

Answer 1

Step-by-step explanation:

ANSWER

Here,given

a=1

d=4−1=3

and,s

n

=287

Now,

s

n

=

2

n

(2a+(n−1)d)

⇒287=

2

n

(2×1+(n−1)3)

⇒287=

2

n

(2+3n−3)

⇒574=n(3n−1)

⇒574=3n

2

−n

⇒3n

2

−n−574=0

onsolvingthequadraticequaton