Math, asked by Rukmanpreet, 11 months ago

fund the amplitude of 1+√3i/√3+i

Answers

Answered by Anonymous
0

hey mate

given here

=(1+i3)/(3+i)

= (1+i3)(3-i)/(3-i)(3+i)

= (3+3i-i- i^2 3)/(3- i^2)

={3+2i -(-1)3}/(3-(-1))

=(23+2i)/4

=(3+i)/2

amplitude

= {(3/2)^2+(1/2)^2}

={(3/4+1/4)

=4/4

=1

=1

I hopes its help's u.

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Answered by gandiharini2007
2

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hope it helps u

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