Question

fund the amplitude of 1+√3i/√3+i

Answer 1

hey mate

given here

=(1+i√3)/(√3+i)

= (1+i√3)(√3-i)/(√3-i)(√3+i)

= (√3+3i-i- i^2 √3)/(3- i^2)

={√3+2i -(-1)√3}/(3-(-1))

=(2√3+2i)/4

=(√3+i)/2

amplitude

= √{(√3/2)^2+(1/2)^2}

=√{(3/4+1/4)

=√4/4

=√1

=1

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@abhi.

Answer 2

Answer:

hope it helps u