fund the amplitude of 1+√3i/√3+i
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hey mate
given here
=(1+i√3)/(√3+i)
= (1+i√3)(√3-i)/(√3-i)(√3+i)
= (√3+3i-i- i^2 √3)/(3- i^2)
={√3+2i -(-1)√3}/(3-(-1))
=(2√3+2i)/4
=(√3+i)/2
amplitude
= √{(√3/2)^2+(1/2)^2}
=√{(3/4+1/4)
=√4/4
=√1
=1
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