Question

Fund the equation of a straight line passingbthrough (1,2) and perpenficular to the line y=7.

Answer 1

Answer:

A(1,2)

B(0,7)

Slope of AB(m1) = 7-2/0-1

= -5

Since the line is perpendicular so,

m1*m2= -1

m2= 1/5

Now, equation of line is

y-y1= m(x-x1)

y-2 =1/5(x-1)

5y-10= x-1

x-5y+9=0

Therefore, the equation is x-5y+9=0

Answer 2

Answer:

A(1,2)

B(0,7)

Slope of AB(m1) = 7-2/0-1

= -5

Since the line is perpendicular so,

m1*m2= -1

m2= 1/5

Now, equation of line is

y-y1= m(x-x1)

y-2 =1/5(x-1)

5y-10= x-1

x-5y+9=0

Therefore, the equation is x-5y+9=0

Step-by-step explanation: