fund the value of k for which the lines (k+1)x +3ky+15=0and 5x+5=0
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Answer:
(k+1)x+3ky+15=0
5x +0.y +5=0
we can find the value of k by using formula
a1/a2=b1/b2=c1/c2
here a1=(k+1),a2=5
b1=3k. ,b2=1
c1=15. ,c2=5
now put these values in the above formula we get
k+1/5=3k/1=(15/5)or3
k+1/5=3,3k/1=3
k+1=3*5,k=3/3
k=15-1,k=1
k=14,1
so the value of k will be(14,1)
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