fund x and y if [-2/3 0/1] [-1/2x]+ 3[ -2/1] =2[y/3]
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Step-by-step explanation:
3x+4y−6=0
12x−5y−3=0
a
1
a
2
+b
1
b
2
=3(12)+4(−5)=26−20=6
a
1
a
2
+b
1
b
2
>0
So the equation of internal angle bisector is
a
1
2
+b
1
2
a
1
x+b
1
y+c
1
=−
a
2
2
+b
2
2
a
2
x+b
2
y+c
2
3
2
+4
2
3x+4y−6
=−
(12)
2
+5
2
12x−5y−3
13(3x+4y−6)=−5(12x−5y−3)
39x+52y−78=−60x+25y+15
99x+27y−93=0
33x+9y−31=0
Taking the other two sides
12x−5y−3=0
4x−3y+12=0
a
1
a
2
+b
1
b
2
=12(4)+(−5)(−3)=63
a
1
a
2
+b
1
b
2
>0
So the equation of internal angle bisector is
a
1
2
+b
1
2
a
1
x+b
1
y+c
1
=−
a
2
2
+b
2
2
a
2
x+b
2
y+c
2
(12)
2
+5
2
12x−5y−3
=−
4
2
+3
2
4x−3y+12
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