Math, asked by jeevan8182, 1 month ago

fundamental operation (3y+4z) (3y-4z)​

Answers

Answered by lakshitasolanki1675
1

Answer:

(3y + 4z) (3y – 4z) + (2y + 7z) (y + z)

= 3y (3y – 4z) + 4z (3y – 4z) + 2y (y + z) (y + z)

= 9y2 – 12yz + 12yz – 16z2 + 2y2 + 2yz + 7yz + 7z2

= (9+2)y2 + (–12 + 12 + 2 + 7)yz + (–16 + 7)z2

= 11y2 + 9yz – 9z2

Step-by-step explanation:

please mark as brainlist

Answered by kaimav1234567
0

Answer:

0

Step-by-step explanation:

(3y+4z)(3y-4z)

= (3y-3y)(-4z-4z)

= 0

if it helps pls mark as bralist

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