fundamental operation (3y+4z) (3y-4z)
Answers
Answered by
1
Answer:
(3y + 4z) (3y – 4z) + (2y + 7z) (y + z)
= 3y (3y – 4z) + 4z (3y – 4z) + 2y (y + z) (y + z)
= 9y2 – 12yz + 12yz – 16z2 + 2y2 + 2yz + 7yz + 7z2
= (9+2)y2 + (–12 + 12 + 2 + 7)yz + (–16 + 7)z2
= 11y2 + 9yz – 9z2
Step-by-step explanation:
please mark as brainlist
Answered by
0
Answer:
0
Step-by-step explanation:
(3y+4z)(3y-4z)
= (3y-3y)(-4z-4z)
= 0
if it helps pls mark as bralist
Similar questions