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The measurement of the electron position is associated
with an uncertainty in momentum which is equal to
1 x 10-18 g cm s-1. The uncertainty in velocity of
electron (mass of electron is 9 x 10-28g) is
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Answer:
Explanation:
Hey there !
Solution:
Given Information:
Mass of electron = 9 × 10³¹ kg => 9 × 10⁻²⁸ g
Uncertainty in Momentum = 1 × 10⁻¹⁸ g
To find :
Uncertainty in position of the electron
Illustration:
Formula to be used:
Momentum ( p ) = Mass ( m ) × Velocity ( v )
=> Δ p = Δ ( m.v )
We know that mass is constant. So we get,
=> Δ p = m Δ v
So we get,
=> Δ v = Δ p / m
Substituting the values in the above equation we get,
=> Δ v = 1 × 10⁻¹⁸ / 9 × 10⁻²⁸
=> Δ v = ( 1 / 9 ) × 10⁻¹⁸⁺²⁸
=> Δ v = 0.1111 × 10¹⁰ cm/s
=> Δ v = 11.11 × 10⁸ cm/s
Therefore the uncertainty in the velocity of an electron is 11.11 × 10⁸ cm/s.
Hope my answer helped !
parvez081:
good work
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