Math, asked by yash25342, 4 months ago

осить ППС разпg ишоирп (-2,
whose sum is zero.
1. Find the equation of the straight line passing through the
Y-intercepts which are in the ratio 2:3.
2. Find the equation of the straight line passing through the poi
line passing through the points (1, 1) and (2,3).
3. Show that the following sets of points are collinear and find th
them.
(1) (-5, 1), (5,5), (10, 7)
(ü) (1, 3), (-2,-6), (2,6)
(iii) (a, b + c), (b, c + a), (c, a + b)
1. A(10,4), B(-4,9) and C(-2, -1) are the vertices of a triang
(i) AB
(ii) the median through A
(iii) the altitude through B
(iv) the perpendicular bisector
Straight line - Normal form - Illustrations
We now prove the theorem relating to the normal form of the equ
scussed in the previous class.
Theorem : The equation of the straight line, whose distan
el ray of which drawn from the origin makes an angle a w
is measured counter clock-wise, is x cos a + y sin a = p.​

Answers

Answered by sehatdhami
0

Answer:

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Answered by devimanju6481
2

Answer:

Let

a

be the x intercept of the line.

Hence y intercept will be −1−a.

Therefore the equation of the line in slope intercept form will be

a

x

+

−1−a

y

=1

Since it passes through (4,3)

a

4

+

−1−a

3

=1

4(−1−a)+3(a)=(−1−a)a

−4−4a+3a=−a−a

2

−4−a=−a−a

2

a

2

=4

a=±2

Hence the equations of the possible lines are

−2

x

+

1

y

=1 and

2

x

+

−3

y

=1

Step-by-step explanation:

I think it's help you

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