Question

(g) (a - 16)(a + 2) find the product ​

Answer 1

Answer:

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Answer 2

Answer: this example sum only $9(a−2) 2 −16(a+2) 2 =[3(a−2)] 2 −[4(a+2)] 2 9(a−2) 2 −16(a+2) 2 =[3(a−2)−4(a+2)][3(a−2)+4(a+2)] [∴a 2 −b 2 =(a+b)(a−b)]9(a−2) 2 −16(a+2) 2 =[3a−6−4a−8][3a−6+4a+8]9(a−2) 2 −16(a+2) 2 =[−a−14][7a+2]9(a−2) 2 −16(a+2) 2 =−[a+14][7a+2]$

Step-by-step explanation:  ⇒(a-16)(a+2)​

We multiply by distributing the terms.

⇒(a)(a)+(a)(2)+(−16)(a)+(−16)(2)

Then simplify the above expression.

⇒a²+2a−16a−32

⇒a²−14a−32

Thus, (a-16)(a+2)​=a²−14a−32.