Question

-G, एक समबाहु त्रिभुज ABC का केंद्रक है।
तदानुसार यदि AB =9 से.मी. हो, तो AG किसके
बराबर होगा?
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Answer 1

Step-by-step explanation:

Here AB=9cm

Let a point from A intersect at point M on the line BC.

As ABC is a equilateral triangle then AM will bisect BC.

SO , BM=BC/2

BM=9/2=4.5cm

Using Pythagoras theorem in Triangle ABM,

AB^2=Bm^2+AM^2

AM=7.8cm

So , AG=AM/2= 7.8/2=3.9~4cm