g=Gm /R^2
Can anyone solve this equation by putting universal values of g,G,m,R
Answers
Answered by
4
hey buddy,
in solving this question we should know their values first.
here,
g is acceleration due to gravity,
G is gravitational constant = 6.67 × 10-¹¹
m is the mass of earth = 6 × 10²⁴
r is the radius of the earth = 6.4 × 10^6(/this vary at different points or places in the earth)
so now putting these values
g = Gm/R²
g = 6.67 × 10-¹¹ × 6 × 10²⁴ /(6.4 × 10^6)²
g = 9.81 approx which is approximately equal to the acceleration due to gravity of earth.
hope it will help
in solving this question we should know their values first.
here,
g is acceleration due to gravity,
G is gravitational constant = 6.67 × 10-¹¹
m is the mass of earth = 6 × 10²⁴
r is the radius of the earth = 6.4 × 10^6(/this vary at different points or places in the earth)
so now putting these values
g = Gm/R²
g = 6.67 × 10-¹¹ × 6 × 10²⁴ /(6.4 × 10^6)²
g = 9.81 approx which is approximately equal to the acceleration due to gravity of earth.
hope it will help
sofreen:
Thanks
Answered by
1
GRAVITATIONAL CONSTANT = 9.8 m/s^2
MASS OF EARTH = 5.96* 10 ^24 kg
RADIUS OF EARTH = 6.37*10^6 m
g = Gm /R^2
g= 9.8 * 5.96 / (6.37*10^6) ^2
g= 58.11 / 4.05 * 10^13
g = 14.34 * 10 ^ - 13 kg m^-1 s^-2
MASS OF EARTH = 5.96* 10 ^24 kg
RADIUS OF EARTH = 6.37*10^6 m
g = Gm /R^2
g= 9.8 * 5.96 / (6.37*10^6) ^2
g= 58.11 / 4.05 * 10^13
g = 14.34 * 10 ^ - 13 kg m^-1 s^-2
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