Question

G. Insert 5 GM's between 32/9 and 8/2​

Answer 1

Answer:

$\frac{8}{2} = \frac{32}{9} {(r)}^{6} \\ \\ {r}^{6} = \frac{9}{8} \\ \\ r = { (\frac{9}{8}) }^{ \frac{1}{6} } = \frac{ {3}^{ \frac{1}{3} } }{ \sqrt{2} } \\ \\ = >a = \frac{32}{9} \\ \\ g.m. = > ar \: \: \: \: a {r}^{2} \: \:a {r}^{3} \: \: a {r}^{4} \: \: \: a {r}^{5}$