G is 27 years older than her wife H. after 8 years she will be twice as old as H. Find their present age .
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Answered by
3
Let age of H be x
age of G = x+27
After 8 years,
age of G = x + 36
age of H= x+8
G= 2H
x+36 = 2(x+8)
x+36 = 2x + 16
x = 20
•°• Present age of G= x+ 27= 47
and present age of H= x= 20
;)
Hope it helps...
age of G = x+27
After 8 years,
age of G = x + 36
age of H= x+8
G= 2H
x+36 = 2(x+8)
x+36 = 2x + 16
x = 20
•°• Present age of G= x+ 27= 47
and present age of H= x= 20
;)
Hope it helps...
arpan61:
no the answer is wrong answer is g- 46 r-19
Answered by
0
let h age=x
age of g= x+27
after 8 yrs=
g's age =x+ 36
h's age =x+8
G=2h
x+36=2(x+8)
x=20
so age of g is 47
and age of h is 20
age of g= x+27
after 8 yrs=
g's age =x+ 36
h's age =x+8
G=2h
x+36=2(x+8)
x=20
so age of g is 47
and age of h is 20
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