Math, asked by arpan61, 1 year ago

G is 27 years older than her wife H. after 8 years she will be twice as old as H. Find their present age .

Answers

Answered by VemugantiRahul
3
Let age of H be x
age of G = x+27

After 8 years,
age of G = x + 36
age of H= x+8

G= 2H
x+36 = 2(x+8)
x+36 = 2x + 16
x = 20

•°• Present age of G= x+ 27= 47
and present age of H= x= 20

;)
Hope it helps...

arpan61: no the answer is wrong answer is g- 46 r-19
Answered by Manvikaur
0
let h age=x
age of g= x+27
after 8 yrs=
g's age =x+ 36
h's age =x+8

G=2h
x+36=2(x+8)
x=20

so age of g is 47
and age of h is 20

arpan61: because I am like Albert Einstein
Manvikaur: ooo
arpan61: so you understand now
arpan61: let friends
arpan61: now your friends ok
arpan61: now we are friends ok thank
arpan61: let the present age of Rekha bxr present age of Mr Goyal X + 27 years age after 8 years equal to X + 27 + 8 years equals + 35 years according to given condition X + 35 equal to 2 into X + 8 or X + 35 equal to 2x + 16 or 2 x minus X equal to 35 - 16 or X equal to 90 Rekha's present age is 19 years present age is 19 + 27 years or 10 years is 46 year
arpan61: sorry there will be no 10
arpan61: here G call to Goyal and H equal to Rekha
arpan61: sorry there will be no call equal
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