g of zn reacted with 15 g of hci to form 18 zncl, and h ,. calculate the mass of zncl, (zn = 65.4 g / mol, h = 1 g / mol and cl = 35.5 g / mol)
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Answer:
Explanation:
At the same time, you have a
2
:
1
mole ratio between hydrochloric acid and hydrogen gas.
This means that the reaction will always produce half as many moles of hydrogen gas as you have moles of hydrochloric acid.
Since you know that
4
moles of hydrochloric acid are taking part in the reaction, and assuming that you have enough zinc metal so that it doesn't act as a limiting reagent, you can say that the reaction will produce
4
moles HCl
⋅
1 mole H
2
2
moles HCl
=
2 moles H
2
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