G or u character of bonding and antibonding atomic structure
Answers
Answer:
Explanation:On the other hand, note that classifying orbitals just by g and u does not make much sense. You should always consider the entire molecule’s point group and thus always consider which (set of) irreducible representation(s) an orbital or a set of orbitals has/have in said point group.
For example considering a set of six atoms arranged in an octahedron around a central atom; each of the surrounding atoms has three p-type orbitals and we are only interested in those that are perpendicular to the outside atom – central atom axis. These twelve p-orbitals transform as t1g+t1u+t2g+t2u. Omitting the t and the subscripted numeral is a non-complete description of the orbitals. Only those in exactly the same irreducible representation will mix in a non-zero fashion.
share