Question

g= t⅔ + 4t and t = 64 find the value of g​

Answer 1

Answer:

272

Step-by-step explanation:

g=t⅔+4t

=(64)⅔+4×64

=(2⁶)⅔+256

=(2)⁴+256

= 16+256

g =272

Answer 2

Answer:

g= (t)^2/3+ 4t. Now given t= 64, g= (64)^2/3 + 4(64). g= [(4)3 ]^2/3 + 256, g= 4^ (3×2/3) + 256. g=4^2+ 256. g= 16+ 256, g= 272. Hence the value of g is 272. Hope this helps you.