Question

G. The natural isotopic abundance of 10B is 19.60% and 11B 80.40 %. The exact isotopic masses are 10.13 and 11.009 respectively. Calculate the average atomic mass of boron​

Answer 1

Answer:

10.84

Explanation:

To find the average atomic mass of boron we divide the abundances by 100% then multiply with the isotopic masses

We then add the results

The following step should be followed

19.60÷100% = 0.196 %

Next we take

80.40 ÷ 100 % = 0.804 %

We then multiply each of them by their isotopic masses

0.196 × 10.13 = 1.9854

0.804 × 11.009 = 8.851

We then add our final answers to get the average atomic masses that is

1.9854 + 8.851 = 10.84

Answer 2

avg. atomic mass = N1×V1+N2×V2/100

10×19.60+11×80.40/100

=10.80