(g) Two coins are tossed 340 times and the outcomes are (i) two tail =115 (ii) one tail =100 (iii) no tail
=125.Find the probability of occurence of (i) one tail (ii) three tail. (2)
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Solution
Given;
⇒Total Number of Two coins Tossed = 340
⇒Number of Two Tails Comes = 115
⇒Number of One Tail Comes = 100
⇒Number of No Tail Comes = 125
Formula
⇒ probability = (No of Favorable outcome)/(Total Number of Favorable Outcome)
So Probability of Occurrence One tail is
⇒(Number of one tail come)/(Total number of coin tossed) = 100/340
Probability of occurrence of three tail is Zero because According to question Two coin is tossed so three tails is not possible
Answer
⇒Probability of Occurrence One tail is 100/340
⇒ Probability of Occurrence Three Tail is Zero
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