Question

g(x) =1-x/1+x then find g(1/x)+g(x)=?​

Answer 1

Step-by-step explanation:

$g( \frac{1}{x }) = 1 - \frac{ \frac{1}{x} }{1 + \frac{1}{x} } = 1 - \frac{1}{x + 1}$

$g(x) + g( \frac{1}{x} ) = 2 - \frac{x + 1}{x + 1} = 1$

Answer 2

$\huge { \:Question} \\ \\ if \: g(x) = \frac{(1 - x)}{(1 + x)} \: then \: find \: g( \frac{1}{x} ) + g(x) \\ \\ \huge \red{ \: solution} \\ \\ firstly \: find \: \: g \bigg(\frac{ 1}{x} \bigg ) \\ \\ put \: x \: = \frac{1}{x} in \: \: \: \: \: \: \frac{(1 - x)}{(1 + x)} \\ \\ \implies \: \frac{1 - \frac{1}{x} }{1 + \frac{1}{x} } \\ \\ \implies \: \frac{x - 1}{x + 1} \\ \: \therefore \: g \bigg( \frac{1}{x} \bigg) + g(x) = \frac{x - 1}{x + 1} + \frac{1 - x}{1 + x} \\ \\ \implies \: \frac{x - 1 + 1 - x}{x + 1} \\ \\ \implies \: \frac{0}{x + 1} = 0$