Math, asked by anihajong16, 7 months ago

g(x)=2/x+1 ,h(x)=(x+2)²-5 Find the equation hg(x)=11

Answers

Answered by imamjan
0

Answer:

g(x)= 2/x+1

h(x)=(x+2)^{2}-5= x^{2}+4x+4

hg(x)=(2/x+1)(x^{2}+4x+4)

hg(x)= 2x+8+8/x+x^{2}+4x+4)

hg(x)=x^{2}+6x+8/x+12= x^{2}+\frac{6xsqrd+8}{x}+12

as, hg(x)=11

x^{2}+\frac{6xsqrd+8}{x}+12=11

x^{3}+6x^{2}+12x+8=11

x^{3}+6x^{2}+12x+8-11=0

x^{3}+6x^{2}+12x-3=0

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