Math, asked by mansi6015, 3 months ago

g( x) = ax^2 + 24
For the function g defined above, a is a constant
and g(4) = 8. What is the value of g(−4) ?

Answers

Answered by rkcomp31
0

Answer:

\bf{ g(-4) =8 }

Step-by-step explanation:

Given that:

g(x)= ax^2 +24-----------(1)\\\\g(4)=8\\\\\Rightarrow  a(4)^2+24=8\\\\\Rightarrow  16a=8-24\\\\\Rightarrow  16a=-16\\\\\Rightarrow  a=-1\\Now\ putting \ a=-1 \ and \ x=-4 \ in\ (1) \\\\g(-4)=(-1)(-4)^2+24\\\\=-16+24\\\\=8

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