Question

g( x) = ax^2 + 24
For the function g defined above, a is a constant
and g(4) = 8. What is the value of g(−4) ?

Answer 1

Answer:

$\bf{ g(-4) =8 }$

Step-by-step explanation:

Given that:

$g(x)= ax^2 +24-----------(1)\\\\g(4)=8\\\\\Rightarrow a(4)^2+24=8\\\\\Rightarrow 16a=8-24\\\\\Rightarrow 16a=-16\\\\\Rightarrow a=-1\\Now\ putting \ a=-1 \ and \ x=-4 \ in\ (1) \\\\g(-4)=(-1)(-4)^2+24\\\\=-16+24\\\\=8$