g(x)=cos2x+4 show that g(2x)+g(–2x)=2g(2x)
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We have f(x)=cos(2x+
4
π
)
dx
dy
=−2sin(2x+
4
π
)
Since,
8
3π
<x<
8
7π
⇒
4
3π
<2x<
4
7π
⇒π<2x+
4
π
<2π
i.e 3
rd
and 4
th
quadrant
So, sin(2x+
4
π
) is negative
⇒
dx
dy
is positive
Hence, f(x) is increasing in the given interval
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