G(x)=sqrt(x+2)/5x and f(x)=1/x2 then domain of fog?
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0
Step-by-step explanation:
Correct option is
E
[
2
3
,∞)
Given, f(x)=
x
and g(x)=2x−3
∴(fog)(x)=f{g(x)}=f{2x−3}=
2x−3
For domain of (fog)(x),
2x−3≥0⇒2x≥3⇒x≥
2
3
Therefore, xε[
2
3
,∞)
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