(g) x - y - x2 + y2
(h) (x+
k) 25
2
1,2
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Answer:
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Step-by-step explanation:
Solution:- (C) 800kJ/mol
Given that the bond dissociation energy of XY,X
2
and Y
2
are in the ratio 1:1:0.5.
Let the bond energy of XY,X
2
and Y
2
be 2x,2x and x respectively.
2
1
X
2
+
2
1
Y
2
⟶XY;ΔH=−200kJ/mol
For the above reaction,
ΔH=∑B.E.
(reactant)
−∑B.E.
(product)
⇒−200=(
2
1
×2x+
2
1
×x)−(2x)
⇒−200=
2
3
x−2x
⇒x=(−200)×(−2)=400
Therefore,
Bond dissociation energy of X
2
=2×400=800kJ/mol
Hence the bond dissociation energy of X
2
is 800kJ/mol.
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