Math, asked by lloydzanepk, 10 days ago

G1,G2,G3............Gn e G.M/s between 4 and 16 then (G1,G2,G3............Gn)^1/n is

Answers

Answered by 007naman
1

Answer:

(G1*G2*G3*........*Gn)^1/n = GM of 4 & 16

=(4*16)^1/2

=8

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