गेहु की एक ढेरी 10.5 मी व्यास और ऊचाई 3 मी वाले एक शंकु के आकार की है¡ इसका आयतन पता करे, इस ढेरी को वर्षा से बचाने के लिये केनवास से ढका जाना है, वाँछित केनवास का छेत्रफल पता कीजिए
Answers
Answered by
13
Solution :-
It is in the shape of a cone.
Diameter = 10.5 m
Radius = 10.5/2 = 5.25 m
Height = 3 m
Volume of cone = 1/3πr²h
⇒ 1/3*22/7*5.25*5.25*3
⇒ 86.625 cu m
So, volume is 86.625 cm³
Curved surface area of cone = πrl
l² = h² + r²
⇒ l² = (3)² + (5.25)²
⇒ l² = 9 + 27.5625
⇒ l² = 36.5625
⇒ l = √36.5625
⇒ l = 6.046
Curved surface area = 22/7*5.25*6.046
= 698.313/7
= 99.759 sq m
So, area of the canvas needed to cover is 99.759 sq m
Answer.
It is in the shape of a cone.
Diameter = 10.5 m
Radius = 10.5/2 = 5.25 m
Height = 3 m
Volume of cone = 1/3πr²h
⇒ 1/3*22/7*5.25*5.25*3
⇒ 86.625 cu m
So, volume is 86.625 cm³
Curved surface area of cone = πrl
l² = h² + r²
⇒ l² = (3)² + (5.25)²
⇒ l² = 9 + 27.5625
⇒ l² = 36.5625
⇒ l = √36.5625
⇒ l = 6.046
Curved surface area = 22/7*5.25*6.046
= 698.313/7
= 99.759 sq m
So, area of the canvas needed to cover is 99.759 sq m
Answer.
Similar questions