Question

गुणोत्तर श्रेणी 2,8, 32,....
......का कौन-सा पद 131072 है?​

Answer 1

In the given G.P.

first term, a = 2

common ratio, r = 4

Let aⁿ = 131072

we know that

${a}^{n} = a {r}^{n - 1} \\ 131072 = 2 \times {4}^{n - 1} \\ 65536 = {4}^{n - 1} \\ {4}^{8} = {4}^{n - 1} \\ \\ 8 = n - 1 \\ n = 9$

Hence, 9th term of the GP is 131072

Answer 2

Answer:

22 times 2 =44