Hindi, asked by kherachohan9445, 10 months ago

गुणनखंड कीजिए : (i) 4p^2- 9q^2 (ii) 63a^2- 112b^2 (iii) 49x^2- 36 (iv) 16x^5- 144x^3 (v) (l + m)^2 -(l - m)^2 (vi) 9x^2 y^2- 16 (vii) (x^2- 2xy + y^2) - z^2 (viii) 25a^2- 4b^2+ 28bc - 49c^2

Answers

Answered by adityaaryaas
2

Answer:

कृपया संलग्न छवि देखें।

Attachments:
Answered by nikitasingh79
3

Answer Explanation:

1)  4p² – 9q²

=(2p)² – (3q)²

[a² - b² = (a + b)(a - b)]

=(2p - 3q)( 2p + 3q)

 

2) 63a² – 112b²

= 7( 9a² -16b²)

= 7[ (3a)² – (4b)²]

[a² - b² = (a + b)(a - b)]

= 7(3a - 4b) (3a + 4b)

 

3) 49x² – 36

= (7x)² –(6)²

[a² - b² = (a + b)(a - b)]

= (7x - 6)( 7x + 6)

 

 4) 16x^5 - 144x³

= 16x³(x²- 9)

= 16x³(x² - 3²)

[a² - b² = (a + b)(a - b)]

= 16x³(x + 3)(x - 3)

 

5) (l + m) ² – (l – m) ²

= [ l + m + l - m][l + m - l + m]

[a² - b² = (a + b)(a - b)]

= 2l × 2m

= 4lm

 

6) 9x² y² – 16

(3xy)² - 4²

[a² - b² = (a + b)(a - b)]

= (3xy - 4)(3xy + 4)

 

7) (x² – 2xy + y²) – z²

=  (x - y)² –z²

[ (a - b)²= a² + b² - 2ab &  a² - b² = (a + b)(a - b)]

= (x - y + z)(x - y - z)

 

8) 25a² – 4b² + 28bc – 49c²

= (5a)² – [(2b)² + 2×2b×7c – (7c)²]

[(a - b)² = a² + b² -2ab]

=(5a)² – (2b - 7c)²

[a² - b² = (a + b)(a - b)]

= (5a - 2b + 7c)(5a + 2b - 7c)

आशा है कि यह उत्तर आपकी अवश्य मदद करेगा।।।।  

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