Question

Gaathi
4 from the given informatien
in the figure find the value of x
(4x+601
((x+20)
​

Answer 1

Answer:

ANSWER

∠TQS=180−∠PQT−∠SQR=180–70–50=60

WKT OQ⊥PR

∠OQS=90−∠SQR=90–50=40

In △OQS

∠OQA=∠OSQ=40

∠QOS=180−∠OQS−∠OSQ=180–40–40=100

Now,

∠QTS=21∠QOS because angle made but n arc at the center is twice the angle made by the arc on any point of circle

∠QTS=2100=50

In △QTS

∠TSQ=180–50−60=70

∠TSO+∠OSQ=70

x=70–40=30∘