Gabriela is building a brick wall. Each row of bricks is 6.5\,\text{cm}6.5cm6, point, 5, start text, c, m, end text tall except that the top row is 1\,\text{cm}1cm1, start text, c, m, end text shorter because it has no mortar. She wants the wall to be 259\,\text{cm}259cm259, start text, c, m, end text tall. Which equation can we use to determine rrr, the number of rows of bricks Gabriela needs in her wall?
Answers
Given : Gabriela is building a brick wall Each row of bricks is 6.5 cm except that the top row which is 1cm shorter
To find : number of rows of bricks Gabriela needs in her wall
Solution:
Each Row Height = 6.5 cm
Last Row height = 6.5cm - 1 = 5 .5 cm
Total Height = 259 cm
Let say number of Rows = R
=> 6.5 ( R - 1) + 5.5 = 259
=> 6.5R - 6.5 + 5.5 = 259
=> 6.5R - 1 = 259
=> 6.5R = 260
=> R = 260/6.5
=> R = 40
Total Number of Rows = 40
Expressions can be used
= > 6.5 ( R - 1) + 5.5 = 259 , 6.5R - 1 = 259
Each Rows height * number of Rows - ( height shorter of last low) = Total Height
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Options:
A.) 6.5 ( r - 1 ) = 259
B.) 6.5r - 1 = 259
C.) 6.5r - r = 259
D.) 6.5 ( r - 1 ) + 1 = 259
Answer:
The answer is:
B.) 6.5r - 1
Step-by-step explanation:
We know we want to reach a height of 259 cm. Let's consider the height of the wall with each row of bricks. Each row increases the height by 6.5 cm.
Row Height
1 (top row) 6.5 - 1
2 6.5 - 1 + 6.5
3 6.5 - 1 + 6.5 + 6.5
. . .
r ?
What's the pattern?
We can rewrite the repeated addition using multiplication.
Row Height Expression
1 (top row) 6.5 - 1 6.5 ⋅ 1 - 1
2 6.5 - 1 + 6.5 6.5 ⋅ 2 − 1
3 6.5 - 1 + 6.5 + 65 6.5 ⋅ 3 − 1
. . .
r 6r − 1 6.5 ⋅ r − 1
So the wall is 6.5r - 1 cm tall when there are r rows of bricks.
Since r represents the number of rows Gabriela needs in her wall, and 6r - 1 represents the height of the wall when it has r rows, we can set up an equation to see how many rows it takes to reach a height of 259 cm.
height of the wall = 259
6.5r − 1 = 259
We can use the equation 6.5r - 1 = 259 to determine r, the number of rows of bricks Gabriela needs in her wall.