Question

Galat hai.

11 = 1 as stated in the question that 1 = 11.

So 11 = 1 simple​

Answer 1

Answer:

$\huge{\red{\boxed{\purple{\boxed{\blue{\boxed{\green{\boxed{\orange{\boxed{\red{\boxed{\stone{\pink{G}\orange{O}\blue{O}\red{D} \: \green{A}\purple{F}\pink{T}\red{E}\blue{R}\green{N}\red{O}{O}{N}}}}}}}}}}}}}}}$

Answer 2

Answer:

\displaystyle\Huge \bf\red{\underline{\underline{ANSWER}}}

ANSWER

Let the speed of the train be x km/hr and the speed of the bus is y km/hr.

So according to question and using

\huge \boxed{\sf{Time = \frac{Distance}{speed}}}

Time=

speed

Distance

Total distance =300 km

Mansi travels 60 km by train and 300−60=240 by bus in 4 minute,

\bf\frac{60}{x} + \frac{240}{y} = \red4

x

60

+

y

240

=4

and 100 km by train, 300−100=200 by bus, and takes 10 minutes more,

\bf {\frac{100}{x} + \frac{200}{y} = 4 + \frac{1}{6} = \frac{24 + 1 }{6} = \purple{\frac{25}{6}}}

x

100

+

y

200

=4+

6

1

=

6

24+1

=

6

25

Now, let

\bf\color{blue}{\frac{1}{x} = a}

x

1

=a

and.

\bf \color{blue}{ \frac{1}{y} = b }

y

1

=b

\bfthen 60a+240b=4.............(1)\bfthen60a+240b=4.............(1)

\bf100a+200b=25/6----(2)100a+200b=25/6−−−−(2)

multiply (1) by 5 and (2) by 6 we get

\bf300a+1200b=20..........(3)300a+1200b=20..........(3)

\bf600a+1200b=25...........(4)600a+1200b=25...........(4)

Subtracting (3) and (4) we get

\bf \green{−300a=−5}−300a=−5

\bf{a = \frac{1}{60}}a=

60

1

Putting the value of a in (1) we get

\bf{60 \times \frac{1}{60} + 240b = 4}60×

60

1

+240b=4

\begin{gathered}\bf240b = 3 \\ \\ \bf b = \frac{1}{80}\end{gathered}

240b=3

b=

80

1

Now ,

\begin{gathered}\bf\frac{1}{x} = a \\ \\ \bf \red{a = 60 km/h \: \blue \bigstar}\end{gathered}

x

1

=a

a=60km/h★

\begin{gathered}\bf\frac{1}{y} = b \\ \\ \bf \red {b = 80 km/h \: \pink \bigstar}\end{gathered}

y

1

=b

b=80km/h★

Hence, the speed of the train is 60 km/hr and the speed of the bus is 80 km/hr.

thanks 4 points....gn✔♠

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