Question

Galilio writs that for angle of projection of a projectile at angles 45+thita and 45-thita their horizontal range describe by the projectile are in the ratio of thita =< 45

Answer 1

Answer:

Galileo writes that for angles of projection of a projectile at angles (45+θ) and (45-θ), the horizontal ranges described by the projectile are in the ratio of (if θ ≤ 45)

(a) 2 : 1

(b) 1 : 2

(c) 1 : 1

(d) 2 : 3

Explanation:

Correct Option (c) 1 : 1

For angle (45°-θ), R = u2sin(90° - 2θ)/g = u2 cos 2θ/g

For angle 45°+θ), R = u2sin(90° + 2θ)/g = u2 cos 2θ/g

Answer 2

1:1

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